From Newsgroup: comp.lang.c

On Sat, 10 Oct 2026 23:02:54 +0200, fir

have asked for that but i got somewhat holes im my memory and i
dont exactly remember sometimes on which i wrote and on which not

the problem is i need this adhos enums strongly and really, but those
'smth' are to shore i could use two of them f('some','thin') but it gets >uglier and such code is like degraded

in fact there could be quite easy solution - it is use string literals
as such tags - i mean you dont need to use strcomp , you just need to
have same string literals have same pointer then

if("cat" == "cat") will return true and
if("cat" == "dog") will return false

I say if int is 4 chars this should return 1 in case of fist line
0 in case the second line

if((*(int*)"cat") == (*(int*)"cat")) return 1
if((*(int*)"cat") == (*(int*)"dog") ) return 0

otherwise there is a need one function that from the pointer check
strings are ugual as strcmp

I think can be too
strcpy(char* a, char* b)
{
if(a==b) return 0;

}

but who is sure a and b point a to 2 strings?

i probably asked that but if so once again

is there way to enforce it to work?

--- Synchronet 3.22a-Linux NewsLink 1.2

From Newsgroup: comp.lang.c

On 2026-10-15 11:36, Rosario19 wrote:

On Sat, 10 Oct 2026 23:02:54 +0200, fir

have asked for that but i got somewhat holes im my memory and i
dont exactly remember sometimes on which i wrote and on which not

the problem is i need this adhos enums strongly and really, but those
'smth' are to shore i could use two of them f('some','thin') but it gets
uglier and such code is like degraded

in fact there could be quite easy solution - it is use string literals
as such tags - i mean you dont need to use strcomp , you just need to
have same string literals have same pointer then

if("cat" == "cat") will return true and
if("cat" == "dog") will return false

I say if int is 4 chars this should return 1 in case of fist line
0 in case the second line

if((*(int*)"cat") == (*(int*)"cat")) return 1
if((*(int*)"cat") == (*(int*)"dog") ) return 0

You are seriously suggesting that the semantics of "C" should
depend on the actual string-length at runtime, that it should
not have an unambiguous uniform semantics in the first place?

Janis

otherwise there is a need one function that from the pointer check
strings are ugual as strcmp

I think can be too
strcpy(char* a, char* b)
{
if(a==b) return 0;

}

but who is sure a and b point a to 2 strings?

i probably asked that but if so once again

is there way to enforce it to work?

--- Synchronet 3.22a-Linux NewsLink 1.2

From Newsgroup: comp.lang.c

On Thu, 15 Oct 2026 12:09:06 +0200, Janis Papanagnou wrote:

On 2026-10-15 11:36, Rosario19 wrote:

On Sat, 10 Oct 2026 23:02:54 +0200, fir

have asked for that but i got somewhat holes im my memory and i
dont exactly remember sometimes on which i wrote and on which not

the problem is i need this adhos enums strongly and really, but those
'smth' are to shore i could use two of them f('some','thin') but it gets >>> uglier and such code is like degraded

in fact there could be quite easy solution - it is use string literals
as such tags - i mean you dont need to use strcomp , you just need to
have same string literals have same pointer then

if("cat" == "cat") will return true and
if("cat" == "dog") will return false

I say if int is 4 chars this should return 1 in case of fist line
0 in case the second line

if((*(int*)"cat") == (*(int*)"cat")) return 1
if((*(int*)"cat") == (*(int*)"dog") ) return 0

You are seriously suggesting that the semantics of "C" should
depend on the actual string-length at runtime, that it should
not have an unambiguous uniform semantics in the first place?

Janis

no, but see x86 assembly result of above in my pc can do that as
aspected
--- Synchronet 3.22a-Linux NewsLink 1.2