We completely replace the foundation of truth conditional
semantics with proof theoretic semantics. Then expressions
are "true on the basis of meaning expressed in language"
only to the extent that all their meaning comes from
inferential relations to other expressions of that language.
This is a purely linguistic PTS notion of truth with no
connections outside the inferential system.
Well-founded proof-theoretic semantics reject expressions
lacking a "well-founded justification tree" as meaningless.
∀x (~Provable(T, x) ⇔ Meaningless(T, x))
On 2026-02-10 21:59, olcott wrote:
We completely replace the foundation of truth conditional
semantics with proof theoretic semantics. Then expressions
are "true on the basis of meaning expressed in language"
only to the extent that all their meaning comes from
inferential relations to other expressions of that language.
This is a purely linguistic PTS notion of truth with no
connections outside the inferential system.
Well-founded proof-theoretic semantics reject expressions
lacking a "well-founded justification tree" as meaningless.
∀x (~Provable(T, x) ⇔ Meaningless(T, x))
Proof-theoretic semantics makes no such claim. That's your claim and you should stop attributing it to others.
André
On 2/11/2026 2:43 PM, André G. Isaak wrote:
On 2026-02-10 21:59, olcott wrote:
We completely replace the foundation of truth conditional
semantics with proof theoretic semantics. Then expressions
are "true on the basis of meaning expressed in language"
only to the extent that all their meaning comes from
inferential relations to other expressions of that language.
This is a purely linguistic PTS notion of truth with no
connections outside the inferential system.
Well-founded proof-theoretic semantics reject expressions
lacking a "well-founded justification tree" as meaningless.
∀x (~Provable(T, x) ⇔ Meaningless(T, x))
Proof-theoretic semantics makes no such claim. That's your claim and
you should stop attributing it to others.
André
That is a correct paraphrase of the claims that it
always does make. Try and show otherwise.
On 2026-02-11 14:27, olcott wrote:
On 2/11/2026 2:43 PM, André G. Isaak wrote:
On 2026-02-10 21:59, olcott wrote:
We completely replace the foundation of truth conditional
semantics with proof theoretic semantics. Then expressions
are "true on the basis of meaning expressed in language"
only to the extent that all their meaning comes from
inferential relations to other expressions of that language.
This is a purely linguistic PTS notion of truth with no
connections outside the inferential system.
Well-founded proof-theoretic semantics reject expressions
lacking a "well-founded justification tree" as meaningless.
∀x (~Provable(T, x) ⇔ Meaningless(T, x))
Proof-theoretic semantics makes no such claim. That's your claim and
you should stop attributing it to others.
André
That is a correct paraphrase of the claims that it
always does make. Try and show otherwise.
Not even remotely.
And the burden of proof is on you to justify your claims. Please quote someone working on PTS who claims that ∀x (~Provable(T, x) ⇔ Meaningless(T, x))
André
On 2/11/2026 5:30 PM, André G. Isaak wrote:
On 2026-02-11 14:27, olcott wrote:
On 2/11/2026 2:43 PM, André G. Isaak wrote:
On 2026-02-10 21:59, olcott wrote:
We completely replace the foundation of truth conditional
semantics with proof theoretic semantics. Then expressions
are "true on the basis of meaning expressed in language"
only to the extent that all their meaning comes from
inferential relations to other expressions of that language.
This is a purely linguistic PTS notion of truth with no
connections outside the inferential system.
Well-founded proof-theoretic semantics reject expressions
lacking a "well-founded justification tree" as meaningless.
∀x (~Provable(T, x) ⇔ Meaningless(T, x))
Proof-theoretic semantics makes no such claim. That's your claim and
you should stop attributing it to others.
André
That is a correct paraphrase of the claims that it
always does make. Try and show otherwise.
Not even remotely.
And the burden of proof is on you to justify your claims. Please quote
someone working on PTS who claims that ∀x (~Provable(T, x) ⇔
Meaningless(T, x))
André
That is fair.
1.2 Inferentialism, intuitionism, anti-realism
Proof-theoretic semantics is inherently inferential,
as it is inferential activity which manifests itself
in proofs. It thus belongs to inferentialism (a term
coined by Brandom, see his 1994; 2000) according to
which inferences and the rules of inference establish
the meaning of expressions
On 2026-02-11 16:41, olcott wrote:
On 2/11/2026 5:30 PM, André G. Isaak wrote:
On 2026-02-11 14:27, olcott wrote:
On 2/11/2026 2:43 PM, André G. Isaak wrote:
On 2026-02-10 21:59, olcott wrote:
We completely replace the foundation of truth conditional
semantics with proof theoretic semantics. Then expressions
are "true on the basis of meaning expressed in language"
only to the extent that all their meaning comes from
inferential relations to other expressions of that language.
This is a purely linguistic PTS notion of truth with no
connections outside the inferential system.
Well-founded proof-theoretic semantics reject expressions
lacking a "well-founded justification tree" as meaningless.
∀x (~Provable(T, x) ⇔ Meaningless(T, x))
Proof-theoretic semantics makes no such claim. That's your claim
and you should stop attributing it to others.
André
That is a correct paraphrase of the claims that it
always does make. Try and show otherwise.
Not even remotely.
And the burden of proof is on you to justify your claims. Please
quote someone working on PTS who claims that ∀x (~Provable(T, x) ⇔
Meaningless(T, x))
André
That is fair.
1.2 Inferentialism, intuitionism, anti-realism
Proof-theoretic semantics is inherently inferential,
as it is inferential activity which manifests itself
in proofs. It thus belongs to inferentialism (a term
coined by Brandom, see his 1994; 2000) according to
which inferences and the rules of inference establish
the meaning of expressions
That doesn't support your position, either the quote above or the entire section in which it is embedded. You're imagining things which simply
aren't there.
André
Please quote someone working on PTS who claims that ∀x (~Provable(T, x)
⇔ Meaningless(T, x))
On 11/02/2026 23:30, André G. Isaak wrote:
Please quote someone working on PTS who claims that ∀x (~Provable(T, x)
⇔ Meaningless(T, x))
Depends on the meaning of "Provable" and of "Meaningless". We don't even
know what objects the system has for quantification, he says it's a syntactical system but I'm starting to think that only has meaning as a specific sort of abstract formal system (semantical, technically).
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